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fgdata/Nasal/std/Vector.nas
2014-10-18 01:13:37 +02:00

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# Copyright (C) 2014 onox
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
var min = func(a, b) { a < b ? a : b }
var max = func(a, b) { a > b ? a : b }
var Vector = {
new: func (vector=nil) {
var m = {
parents: [Vector]
};
if (vector == nil) {
vector = [];
}
m.vector = vector;
return m;
},
size: func {
# Return the number of items in the vector
return size(me.vector);
},
clear: func {
# Remove all items from the vector, resulting in an empty vector
me.vector = [];
},
append: func (item) {
# Append the given item at the end of the vector
append(me.vector, item);
},
extend: func (other_vector) {
# Extend the vector with another vector, appending the items of
# the other vector to this vector
me.vector = me.vector ~ other_vector;
},
insert: func (index, item) {
# Insert the given item at the given index before the old item
# at that index. Any index greater than n-1 where n is the size of
# the vector will append the given item at the end. Any index smaller
# or equal to -n will insert the item at the beginning of the vector.
#
# For example, if the vector contains ["a", "b", "c"], then the
# following operations can happen:
#
# insert(0, "d") => ["d", "a", "b", "c"]
# insert(2, "e") => ["a", "b", "e", "c"]
# insert(3, "f") => ["a", "b", "c", "f"]
# insert(-3, "g") => ["f", "a", "b", "c"]
index = min(index, me.size());
if (index < 0) {
index = max(0, me.size() + index);
}
me.vector = subvec(me.vector, 0, index) ~ [item] ~ subvec(me.vector, index);
},
pop: func (index=nil) {
# Remove and return the item at the given index. If index
# is not given, then it will remove and return the last item.
# A negative index represents the position from the end.
#
# For example, if the vector contains ["a", "b", "c"], then the
# following operations can happen:
#
# pop(0) => "a"
# pop(2) => "c"
# pop(-1) => "c"
# pop(-3) => "a"
#
# Thus the range is -n .. n-1 where n is the size of the vector.
# IndexError is raised if the index is out of range.
if (index != nil) {
if (index < -me.size() or index >= me.size()) {
die("IndexError: index out of range");
}
if (index < 0) {
index = me.size() + index;
}
var item = me.vector[index];
me.vector = subvec(me.vector, 0, index) ~ subvec(me.vector, index + 1);
return item;
}
else {
return pop(me.vector);
}
},
index: func (item) {
# Return first index of the given item. Raises a ValueError
# if the item is not in the vector.
forindex (var index; me.vector) {
if (me.vector[index] == item) {
return index;
}
};
die("ValueError: item not in the vector");
},
remove: func (item) {
# Remove the first occurrence of the given item. Raises a
# ValueError if the item is not present in the vector.
me.pop(me.index(item));
}
};