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- fix behavior for broken input

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- more documentation
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mfranz 2007-06-22 17:52:37 +00:00
parent bf2794eef6
commit 248d4fcf60
1 changed files with 5 additions and 5 deletions
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10
Nasal/string.nas
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@ -68,24 +68,24 @@ var imatch = func(a, b) match(lc(a), lc(b));
# \? stands for a question mark (not "any single character") # \? stands for a question mark (not "any single character")
# [] stands for a group of characters: # [] stands for a group of characters:
# [abc] stands for letters a or b or c # [abc] stands for letters a or b or c
# [^abc] stands for any letter but any of a, b, and c # [^abc] stands for any character but any of a, b, and c
# [1-4] stands for digits 1 to 4 (1, 2, 3, 4) # [1-4] stands for digits 1 to 4 (1, 2, 3, 4)
# [1-4-] stands for digits 1 to 4 (1, 2, 3, 4), and the minus # [1-4-] stands for digits 1 to 4, and the minus
# [-1-4] same as above # [-1-4] same as above
# [1-3-6] stands for digits 1 to 3, minus, and 6 # [1-3-6] stands for digits 1 to 3, minus, and 6
# [1-3-6-9] stands for digits 1 to 3, minus, and 6 to 9 # [1-3-6-9] stands for digits 1 to 3, minus, and 6 to 9
# [][] stands for the closing bracket and the opening bracket # [][] stands for the closing and the opening bracket (']' must come first!)
# [^^] stands for all characters but the caret symbol # [^^] stands for all characters but the caret symbol
# #
# Example: # Example:
# string.match(file, "*[0-9].xml"); ... true if string ends with digit followed by ".xml" # string.match(name, "*[0-9].xml"); ... true if 'name' ends with digit followed by ".xml"
# #
var match = func(str, patt) { var match = func(str, patt) {
var s = 0; var s = 0;
for (var p = 0; p < size(patt) and s < size(str); ) { for (var p = 0; p < size(patt) and s < size(str); ) {
if (patt[p] == `\\`) { if (patt[p] == `\\`) {
if ((p += 1) >= size(patt)) if ((p += 1) >= size(patt))
return !size(str); # pattern ends with backslash return 0; # pattern ends with backslash
} elsif (patt[p] == `?`) { } elsif (patt[p] == `?`) {
s += 1; s += 1;