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- check for availability of MP models (add 'available' member)

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- display "??? foo" if "foo" isn't available on the system
- make sure x/y/z are never nil (I think I had such a case)
This commit is contained in:
mfranz 2009-02-03 16:15:37 +00:00
parent 5ac4c13406
commit 158c7ea800
1 changed files with 19 additions and 6 deletions
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25
Nasal/multiplayer.nas
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@ -267,13 +267,13 @@ var dialog = {
foreach (var mp; model.list) {
var n = mp.node;
var ac = geo.Coord.new().set_xyz(
n.getNode("position/global-x").getValue(),
n.getNode("position/global-y").getValue(),
n.getNode("position/global-z").getValue());
n.getNode("position/global-x").getValue() or 0,
n.getNode("position/global-y").getValue() or 0,
n.getNode("position/global-z").getValue() or 0);
var distance = self.distance_to(ac);
n.setValues({
"model-short": mp.model,
"model-short": mp.available ? mp.model : "??? " ~ mp.model,
"bearing-to": self.course_to(ac),
"distance-to-km": distance / 1000.0,
"distance-to-nm": distance * M2NM,
@ -360,6 +360,8 @@ var model = {
return;
me.data = {};
me.callsign = {};
var root = string.normpath(getprop("/sim/fg-root")) ~ '/';
foreach (var n; props.globals.getNode("ai/models", 1).getChildren("multiplayer")) {
if (!n.getNode("valid", 1).getValue())
continue;
@ -368,13 +370,24 @@ var model = {
continue;
var model = n.getNode("sim/model/path").getValue();
var available = 0;
if (io.stat(string.normpath(root ~ "AI/" ~ model)) != nil)
available = 1;
elsif (io.stat(string.normpath(root ~ model)) != nil)
available = 2;
else
print("Multiplayer model not available: ", model);
model = split(".", split("/", model)[-1])[0];
model = me.remove_suffix(model, "-model");
model = me.remove_suffix(model, "-anim");
var path = n.getPath();
me.data[path] = { node: n, callsign: callsign, model: model,
path: path, sort: string.lc(callsign)};
var data = { node: n, callsign: callsign, model: model, path: path,
sort: string.lc(callsign), available: available };
me.data[path] = data;
me.callsign[callsign] = data;
}
me.list = sort(keys(me.data), func(a, b) cmp(me.data[a].sort, me.data[b].sort));